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4a^2-12a-40=0
a = 4; b = -12; c = -40;
Δ = b2-4ac
Δ = -122-4·4·(-40)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-28}{2*4}=\frac{-16}{8} =-2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+28}{2*4}=\frac{40}{8} =5 $
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